Egm 510 – Decision Making
[pic 1]Engineering and Technology ManagementEGM 510Assignment 2Decision MakingEman Alshuweihi201410538Question (1):Alphabet Blocks (B):  1 hour of wood working and 2 hours of painting.Wooden Trucks  (T):  3 hours of wood working and one hour of painting.The problem:How many boxes of blocks (B) and trucks (T) should you make each week to maximize profit?Decision variable: Let (B) = number of boxes of Alphabet blocks per weekLet (T) = number of boxes of Wooden trucks per weekObjective Function:profit is $30 per box of blocks and $40 per box of trucks.Maximize     P= 30B + 40TConstraints:(each working 40 hours per week) employ three wood workers and two painters1B + 3T ≤ 120         1 hour of wood working and 2 hours of painting. 2B + 1T ≤ 80           3 hours of wood working and one hour of painting. solve two Equations:[pic 2]                                                                  2B + 1T ≤ 80    Mult.  by (-2)        1B + 3T ≤ 120         -2B – 6T ≤ -240[pic 3][pic 4][pic 5]                                                                     -5 T ≤ -160            T =32[pic 6]   2B + 1T ≤ 80             2B + 1(32) ≤ 80       B=24[pic 7][pic 8]The profit that can the company get by those numbers of boxes:P= 30B + 40T   P= 30(24) + 40(32) = $2000   So, the company can reach the maximum profit that equals $2000 by making 24 boxes of blocks and 32 boxes of trucks weekly.

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