Essay About Item B And No. Of Item D

Chapter 5 Problem 28
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Homework 2Chapter 5 Problem 28Decision variables: xij =1 [if assign professor i to course j]xij =0 [if not assign professor i to course j]i= Strausbaygh (S), Kelley (K), Davidson (D), Merkle (M) j= Statistics (1), Management (2), Finance (3), Economics (4)Objectives: Max [pic 1]rij is the rating that professor i teaches course jConstraints: Professor nodes:xS1+xS2+xS3+xS4=1 xK1+xK2+xK3+xK4 =1 xD1+xD2+xD3+xD4 =1 xM1+xM2+xM3+xM4 =1Course nodes:xS1+xK1+xD1+xM1=1 xS2+xK2+xD2+xM2=1 xS3+xK3+xD3+xM3=1 xS4+xK4+xD4+xM4=1Solution:Strausbaygh:  EconomicsKelley: Management, Davidson: Finance,                Merkle: StatisticsOptimal ratings: 310Attach spreadsheet: (CH5_Q28)Chapter 6 Problem 20Decision variables: A= No. of item A to be shipped B= No. of item B to be shipped C= No. of item C to be shippedD= No. of item D to be shipped E= No. of item E to be shipped F= No. of item F to be shippedG= No. of item G to be shippedObjectives: Maximize valueMax 1800A+1400B+1100C+900D+1600E+1100F+1200GConstraints: Maximum capacity=2200,700A+600B+450C+400D+650E+350F+600G <= 2200At least 2 items of B,C and D,B+C+D >= 2If B is selected, G cannot be selected,B+G <= 1Nonnegative constraint, A, B, C, D, E, F, G = IntegersSolution:Optimal decision: A=0, B=0, C=0, D=2, E=0, F=4, G=0Optimal objective value: 6200Attach spreadsheet: CH6_Q20Chapter 6 Problem 42Decision variables: QA = No. of Product A QB = No. of Product B PA = Price of Product A: [(5500-QA)/200]PB = Price of Product B: [(4500-QB)/225]Objectives: Maximize profitMax [(PA-18) *QA] + [(PB-12) *QB]Constraints: Weekly production capacity for A=275: QA <= 275Weekly production capacity for B=350: QB <= 350700 labor hours available: QA+2QB <= 700Nonnegative constraint: QA and QB ≥ 0