Week 5 – Test Sydney University – Coursework – matt666
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Week 5 – Test Sydney University
sample week 5 test, a)Suppose 10 students do a test and the marks are 20,30,20,40,50,50,50,30,20,50, table and histogram describes the distribution of the variable marks find the missing values on the table Markfrequency 20The number of student that get the mark of 20 = 3 30The number of students that get the mark of 30 = 24050[pic 1]Solution Markfrequency 20The number of student that get the mark of 20 = 3 30The number of students that get the mark of 30 = 240The number of students that get the mark of 40 = 150The number of students that get the mark of 50 = 42 b) Suppose 10 students do a test and the marks are 20,30,20,40,50,50,50,30,20,50,The both the table and percentile plot given below describes the distribution of the variable marks, find the missing values in the table MarkProportion of marks less than the mark on the current row 20 P(Mark <20) = 0/10=0 (0 out of 10 students got a mark less than 20 ) 30P(Mark<30) = 3/10=0.3 (3 out of 10 students got a mark less than 30 )40P(Mark<40) =50P(mark<50) = [pic 2]Solution MarkProportion of marks less than the mark on the current row 20 P(Mark <20) = 0/10=0 (0 out of 10 students got a mark less than 20 ) 30P(Mark<30) = 3/10=0.3 (3 out of 10 students got a mark less than 30 )40P(Mark<40) =5/10=0.5 ( 5 out of 10 students got a mark less than 40 ) 50P(mark<50) = 6/10=0.6 ( 6 out of 10 students got a mark less than 50 )3(c) Suppose 10 students do a test and the marks are 20,30,20,40,50,50,50,30,20,50,The both the table and percentile plot given below describes the distribution of the variable marks, find the missing values in the tableMarkProportion of marks less than or equal to the mark on the current row 20 P(Mark ≤20) = 3/10=0.3 (3 out of 10 students got a mark less than or equal to 20 ) 30P(Mark≤30) = 5/10=0.5 (5 out of 10 students got a mark less than or equal to 30 )20 P(Mark ≤20) = 3/10=0.3 (3 out of 10 students got a mark less than or equal to 20 ) 40P(Mark≤40) =50P(mark≤50) = 10/10=1 (10 out of 10 students got a mark less than or equal to 50 )50P(Mark ≤50)= 10/10=1 (10 out of 10 students got a mark less than or equal to 50 )50P(Mark ≤50)= 10/10=1 (10 out of 10 students got a mark less than or equal to 50)30P(Mark≤30) = 5/10=0.2 (5 out of 10 students got a mark less than or equal to 30 )50P(Mark ≤50)= 10/10=1 (10 out of 10 students got a mark less than or equal to 50 )
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By: matt666
Submitted: October 25, 2015
Essay Length: 2,330 Words / 10 Pages
Paper type: Coursework Views: 441
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Essay About Animal Testing And Distribution Of The Variable Marks
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