Management Chapter 6 Problem 2
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CHAPTER 6 PROBLEM 2Let us define our variables:X11 = Quantity shipped from Jefferson City to Des MoinesX12 = Quantity shipped from Jefferson City to Kansas CityX13 = Quantity shipped from Jefferson City to St. LouisX21= Quantity shipped from Omaha to Des MoinesX22= Quantity shipped from Omaha to Kansas CityX23= Quantity shipped from Omaha to St. LouisObjective function:Min 14X11 + 9X12+ 7X13+8X21+10X22+5X23Subject to:X11 + X12 + X13 <= 30 X21 + X22 + X23 <= 20X11 + X21 = 25 X12 + X22 = 15 X13 + X23 = 10X11, X12, X13, X21, X22. X23 >= 0 (greater or equal to 0)Optimal solution using solver in excel:5 units have to be shipped from Jefferson city to Des Moines for a cost of $7015 units have to be shipped from Jefferson City to Kansas for a cost of $13510 units have to be shipped from Jefferson City to St Louis for a cost of $1020 units have to be shipped from Omaha to Des Moines for a costo f $1600 units Will be shipped from Omaha to Kansas City0 units will be shipped from Omaha to St LouisFollowing this combination, our optimal solution will lead us to a minimum total cost of $435CHAPTER 6 PROBLEM 3A.[pic 1]500 10 400[pic 2][pic 3][pic 4][pic 5][pic 6][pic 7][pic 8] 20[pic 9][pic 10] 200400 12 15[pic 11] 15 18 300B. Let us define our variables:X11 = Quantity shipped from Southern Gas to HamiltonX12 = Quantity shipped from Southern gas to ButlerX13 = Quantity shipped from Southern gas to ClermontX21= Quantity shipped from Northwest gas to HamiltonX22= Quantity shipped from Northwest gas to ButlerX23= Quantity shipped from Northwest gas to ClermontObjective function:Min 10X11 + 20X12+ 15X12+12X21+15X22+18X23Subject to:X11 + X12 + X13 <= 500 X21 + X22 + X23 <= 400X11 + X21 = 400
Essay About Jefferson City And Optimal Solution
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Latest Update: June 7, 2021
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