Stats Solution
Problem set 1Difference between 2 means = Sample mean salary male ā sample mean salary female = 3When the population standard deviation is known and sample size > 30, we use the the Z distribution else we use t distribution. Answer would be a)3)Standard deviation = SE = sqrt[ (s12/n1) + (s22/n2) ]where s1Ā is the standard deviationĀ of sample 1, s2Ā is the standard deviation of sample 2, n1Ā is the size of sample 1, and n2Ā is the size of sample 2.Answer would be d) 4) Margin of error = ZĪ±/2Ā Ļ = 1.96*2 = 3.925) b) is the correct hypothesis6) We established that we would be using Z distribution.Z score = point estimate / standard deviation = 3/2 = 1.57) Refer the Z table Get the p value at Z score = 0.9332Required value = 1- 0.9332 = 0.0668
8) Since p value = 0.0668 > 0.05, we donāt reject the null hypothesis and conclude that the population salaries and males and females are equalProblem set 2Point estimate = Downtown store sample mean ā North mall store sample mean = 9-8 = 1When the population standard deviation is known and sample size > 30, we use the the Z distribution, else we use t distribution. This, we would use t distributionStandard deviation =SE = sqrt[ (s12/n1) + (s22/n2) ]where s1Ā is the standard deviationĀ of sample 1, s2Ā is the standard deviation of sample 2, n1Ā is the size of sample 1, and n2Ā is the size of sample 2.Answer would be c) 0.46a) is the correct hypothesis optionT score = point estimate / standard deviation = 1/ 0.46 =2.17Refer the t table. Use degrees of freedom as 37. T critical value = t0.025Ā = 2.026Since t score > t critical value, we reject the null hypothesis. Thus, the population average wage of downtown store is significantly different from that of north mall store Problem set 3Point estimate = d= mean of all diĀ = (2 ā 4 -2 +0 -1) = -5/5 = -1Standard deviation =sdĀ = sqrt [ (Ī£(diĀ –Ā d)2Ā / (n – 1) ]Ā where diĀ is the difference for pairĀ i,Ā dĀ is the sample mean of the differences, and n is the number of paired values.Use the formula to get the answer