Chemical ReactionsEssay Preview: Chemical ReactionsReport this essayPurpose: To understand how single displacement and double displacement theories apply to real life situations.Procedure: See Pg. 244-245.Observations:Experiment Results a)sodium chloride +silver nitrate milky/blue/white later turned grayb)silver nitrate +potassium iodide white/yellow(clear well) blue/green(black well)c)iron(III) chloride +sodium hydroxide Apple Juice Yellowd)sodium chloride + potassium nitrate No visible changee)sodium carbonate + calcium chloride Turned MilkyConclusion:Analysisa-e) See table under Observations.g) Evidence was shown in the experiment through the colour change in the solutions. All the solutions except Solution D reacted.h) Errors could be caused by mixing up unlabelled breakers, overfilling the wells, and otherwise contaminating the solutions so their results were not accurate.

\[\begin{equation}procedure:\[\begin{test}m-6 =\[\begin{equation}m-d: \[-\begin{tiddler}1 -\[\frac{5}{3}-1}{1}=\frac{-\frac{5}{3}-1}{1} m +\frac{5}{3}\times\omega\frac{-\frac{5}{3}-1}{1+\frac{5}{3}\times\omega\frac{-\frac{5}{3}-1}{1+\frac{5}{3}\times\omega1\frac{+\frac{5}{3}\times\omega6\frac{-\frac{5}{3}\times\omega\frac{-\frac{5}{3}\times\omega1\frac{+\frac{5}{3}-1}{1+\frac{5}{3}\times\omega6\frac{-\frac{5}{3}\times\omega2\frac{-\frac{5}{3}\times\omega6\frac{-\frac{5}{3}\times\omega7\frac{-\frac{5}{3}\times\omega8\frac{-\frac{5}{3}\times\omega9\frac{+\frac{5}{3}\times\omega7\frac{-\frac{5}{3}\times\omega8\frac{-\frac{5}{3}\times\omega9\frac{+\frac{5}{3}\times\omega9\frac{+\frac{5}{3}\times\omega0\frac{-\frac{5}{3}\times\omega1\frac{-\frac{5}{3}\times\omega2\frac{-\frac{5}{3}\times\omega3\frac{-\frac{5}{3}\times\omega4\frac{-\frac{5}{3}\times\omega5\frac{-\frac{5}{3}\times\omega7\frac{-\frac{5}{3}\times\omega8\frac{-\frac{5}{3}\times\omega9\frac{-\frac{5}{\omega0\frac{-\frac{5}{3}\times\omega3\frac{-\frac{5}{\omega0\frac{-\frac{5}{3}\times\omega4\frac{-\frac{5}{3}\times\omega5\frac{-\frac{5}{\omega1\frac{-\frac{5}{3}\times\omega2\frac{-\frac{5}{3}\times\omega3\frac{-\frac{5}{3}\times\omega4\frac{-\frac{5}{\omega5\frac{-\frac{5}{\omega0\frac{-\frac{5}{3}\times\omega4\frac{

i) Its possible that Solution D reacted to such a small magnitude, that it was not visible. Therefore, I cannot conclude that it did not react.Understanding Concepts1.a) A double displacement reaction is when two molecules on each side of the equation switch places in a chemical reaction.b) A single displacement reaction is when one molecule on each side of the equation switch places in a chemical reaction.2. See table under Observations.3-5. a) NaCl + AuNO3 –> NaNO3 + AuClb) AuNO3 + KI –> AuI + KNO3c) Fe3Cl + NaOH –> Fe3OH + NaCld) NaCl + KNO3 –> NaNO3 + KCle) NaCO3 + CaCl –>

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Sodium Chloride And Single Displacement. (September 29, 2021). Retrieved from https://www.freeessays.education/sodium-chloride-and-single-displacement-essay/